Base | Representation |
---|---|
bin | 100000000010101101… |
… | …011110000101111101 |
3 | 10021210202110212221011 |
4 | 200002231132011331 |
5 | 1030430213300131 |
6 | 23445555035221 |
7 | 2325410324050 |
oct | 400255360575 |
9 | 107722425834 |
10 | 34405212541 |
11 | 13655933457 |
12 | 680229bb11 |
13 | 3323c3183b |
14 | 194551ca97 |
15 | d657420b1 |
hex | 802b5e17d |
34405212541 has 4 divisors (see below), whose sum is σ = 39320242912. Its totient is φ = 29490182172.
The previous prime is 34405212529. The next prime is 34405212557. The reversal of 34405212541 is 14521250443.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 34405212541 - 213 = 34405204349 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (34405212341) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2457515175 + ... + 2457515188.
It is an arithmetic number, because the mean of its divisors is an integer number (9830060728).
Almost surely, 234405212541 is an apocalyptic number.
It is an amenable number.
34405212541 is a deficient number, since it is larger than the sum of its proper divisors (4915030371).
34405212541 is an equidigital number, since it uses as much as digits as its factorization.
34405212541 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4915030370.
The product of its (nonzero) digits is 19200, while the sum is 31.
Adding to 34405212541 its reverse (14521250443), we get a palindrome (48926462984).
The spelling of 34405212541 in words is "thirty-four billion, four hundred five million, two hundred twelve thousand, five hundred forty-one".
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