Base | Representation |
---|---|
bin | 110010000100110010001… |
… | …101010000011010100011 |
3 | 110011222002221200221110212 |
4 | 302010302031100122203 |
5 | 422334343422440003 |
6 | 11152454042044335 |
7 | 503416641040115 |
oct | 62046215203243 |
9 | 13158087627425 |
10 | 3441111140003 |
11 | 1107404590039 |
12 | 476ab11a96ab |
13 | 1bc6594a1b94 |
14 | bc79d0653b5 |
15 | 5e7a045add8 |
hex | 321323506a3 |
3441111140003 has 2 divisors, whose sum is σ = 3441111140004. Its totient is φ = 3441111140002.
The previous prime is 3441111139997. The next prime is 3441111140063. The reversal of 3441111140003 is 3000411111443.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3441111140003 - 228 = 3440842704547 is a prime.
It is not a weakly prime, because it can be changed into another prime (3441111140063) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1720555570001 + 1720555570002.
It is an arithmetic number, because the mean of its divisors is an integer number (1720555570002).
Almost surely, 23441111140003 is an apocalyptic number.
3441111140003 is a deficient number, since it is larger than the sum of its proper divisors (1).
3441111140003 is an equidigital number, since it uses as much as digits as its factorization.
3441111140003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 3441111140003 its reverse (3000411111443), we get a palindrome (6441522251446).
The spelling of 3441111140003 in words is "three trillion, four hundred forty-one billion, one hundred eleven million, one hundred forty thousand, three".
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