Base | Representation |
---|---|
bin | 1100110100101010… |
… | …1100011101000111 |
3 | 22212212222110112021 |
4 | 3031022230131013 |
5 | 24022141222212 |
6 | 1325320504011 |
7 | 151204434421 |
oct | 31512543507 |
9 | 8785873467 |
10 | 3442132807 |
11 | 1506aa3363 |
12 | 80091b007 |
13 | 42b188399 |
14 | 249217811 |
15 | 1522cb307 |
hex | cd2ac747 |
3442132807 has 2 divisors, whose sum is σ = 3442132808. Its totient is φ = 3442132806.
The previous prime is 3442132769. The next prime is 3442132831. The reversal of 3442132807 is 7082312443.
It is a strong prime.
It is an emirp because it is prime and its reverse (7082312443) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3442132807 - 211 = 3442130759 is a prime.
It is a super-2 number, since 2×34421328072 = 23696556522051398498, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3442132847) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1721066403 + 1721066404.
It is an arithmetic number, because the mean of its divisors is an integer number (1721066404).
Almost surely, 23442132807 is an apocalyptic number.
3442132807 is a deficient number, since it is larger than the sum of its proper divisors (1).
3442132807 is an equidigital number, since it uses as much as digits as its factorization.
3442132807 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 32256, while the sum is 34.
The square root of 3442132807 is about 58669.6924058751. The cubic root of 3442132807 is about 1509.8803769102.
The spelling of 3442132807 in words is "three billion, four hundred forty-two million, one hundred thirty-two thousand, eight hundred seven".
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