Base | Representation |
---|---|
bin | 1111101010000010111001… |
… | …01000101011111100000111 |
3 | 11111220110212201212010100212 |
4 | 13311001130220223330013 |
5 | 14003100131033424333 |
6 | 201120532411030035 |
7 | 10152325536251411 |
oct | 765013450537407 |
9 | 144813781763325 |
10 | 34430012014343 |
11 | aa74760214660 |
12 | 3a4092543b31b |
13 | 162997558678a |
14 | 8705c87439b1 |
15 | 3ea90c37b448 |
hex | 1f505ca2bf07 |
34430012014343 has 4 divisors (see below), whose sum is σ = 37560013106568. Its totient is φ = 31300010922120.
The previous prime is 34430012014309. The next prime is 34430012014403. The reversal of 34430012014343 is 34341021003443.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 34430012014343 - 216 = 34430011948807 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (34430012014843) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1565000546096 + ... + 1565000546117.
It is an arithmetic number, because the mean of its divisors is an integer number (9390003276642).
Almost surely, 234430012014343 is an apocalyptic number.
34430012014343 is a deficient number, since it is larger than the sum of its proper divisors (3130001092225).
34430012014343 is a wasteful number, since it uses less digits than its factorization.
34430012014343 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3130001092224.
The product of its (nonzero) digits is 41472, while the sum is 32.
Adding to 34430012014343 its reverse (34341021003443), we get a palindrome (68771033017786).
The spelling of 34430012014343 in words is "thirty-four trillion, four hundred thirty billion, twelve million, fourteen thousand, three hundred forty-three".
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