34443031341 has 4 divisors (see below), whose sum is σ = 45924041792. Its totient is φ = 22962020892.

The previous prime is 34443031327. The next prime is 34443031393. The reversal of 34443031341 is 14313034443.

34443031341 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14313034443 = 3 ⋅4771011481.

It is not a de Polignac number, because 34443031341 - 2¹⁰ = 34443030317 is a prime.

It is a super-3 number, since 3×34443031341³ (a number of 33 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 34443031299 and 34443031308.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (34443031321) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5740505221 + ... + 5740505226.

It is an arithmetic number, because the mean of its divisors is an integer number (11481010448).

Almost surely, 2^34443031341 is an apocalyptic number.

It is an amenable number.

34443031341 is a deficient number, since it is larger than the sum of its proper divisors (11481010451).

34443031341 is a wasteful number, since it uses less digits than its factorization.

34443031341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11481010450.

The product of its (nonzero) digits is 20736, while the sum is 30.

Adding to 34443031341 its reverse (14313034443), we get a palindrome (48756065784).

The spelling of 34443031341 in words is "thirty-four billion, four hundred forty-three million, thirty-one thousand, three hundred forty-one".