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34455052450373 is a prime number
BaseRepresentation
bin1111101010110001100010…
…01010010111101001000101
311111222212111211212001222112
413311120301022113221011
514004002421411402443
6201140233234310405
710154203214405162
oct765306112275105
9144885454761875
1034455052450373
11aa8433a959895
123a45753428405
13162c1362aa129
148718c2215069
153eb3c5889b18
hex1f5631297a45

34455052450373 has 2 divisors, whose sum is σ = 34455052450374. Its totient is φ = 34455052450372.

The previous prime is 34455052450321. The next prime is 34455052450393. The reversal of 34455052450373 is 37305425055443.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 32511640802404 + 1943411647969 = 5701898^2 + 1394063^2 .

It is a cyclic number.

It is not a de Polignac number, because 34455052450373 - 238 = 34180174543429 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (34455052450393) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17227526225186 + 17227526225187.

It is an arithmetic number, because the mean of its divisors is an integer number (17227526225187).

Almost surely, 234455052450373 is an apocalyptic number.

It is an amenable number.

34455052450373 is a deficient number, since it is larger than the sum of its proper divisors (1).

34455052450373 is an equidigital number, since it uses as much as digits as its factorization.

34455052450373 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15120000, while the sum is 50.

The spelling of 34455052450373 in words is "thirty-four trillion, four hundred fifty-five billion, fifty-two million, four hundred fifty thousand, three hundred seventy-three".