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34505000837 is a prime number
BaseRepresentation
bin100000001000101010…
…001000011110000101
310022001201020122201222
4200020222020132011
51031131240011322
623503521530125
72331031445036
oct401052103605
9108051218658
1034505000837
11136a719a91a
12682b7a3945
13333b7ccb78
141954896a8d
15d6e3a3e42
hex808a88785

34505000837 has 2 divisors, whose sum is σ = 34505000838. Its totient is φ = 34505000836.

The previous prime is 34505000819. The next prime is 34505000839. The reversal of 34505000837 is 73800050543.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 17404469476 + 17100531361 = 131926^2 + 130769^2 .

It is an emirp because it is prime and its reverse (73800050543) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 34505000837 - 214 = 34504984453 is a prime.

It is a super-2 number, since 2×345050008372 (a number of 22 digits) contains 22 as substring.

Together with 34505000839, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 34505000797 and 34505000806.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (34505000839) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17252500418 + 17252500419.

It is an arithmetic number, because the mean of its divisors is an integer number (17252500419).

Almost surely, 234505000837 is an apocalyptic number.

It is an amenable number.

34505000837 is a deficient number, since it is larger than the sum of its proper divisors (1).

34505000837 is an equidigital number, since it uses as much as digits as its factorization.

34505000837 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 50400, while the sum is 35.

The spelling of 34505000837 in words is "thirty-four billion, five hundred five million, eight hundred thirty-seven", and thus it is an aban number.