Base | Representation |
---|---|
bin | 110010001110000010110… |
… | …111011010101110001111 |
3 | 110012220202220112000110101 |
4 | 302032002313122232033 |
5 | 423020224400213033 |
6 | 11201220434351531 |
7 | 504221225403625 |
oct | 62160267325617 |
9 | 13186686460411 |
10 | 3451054304143 |
11 | 1110647205466 |
12 | 478a0712b5a7 |
13 | 1c058247c664 |
14 | bd063831515 |
15 | 5eb8333d97d |
hex | 32382ddab8f |
3451054304143 has 2 divisors, whose sum is σ = 3451054304144. Its totient is φ = 3451054304142.
The previous prime is 3451054304129. The next prime is 3451054304149. The reversal of 3451054304143 is 3414034501543.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3451054304143 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3451054304149) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1725527152071 + 1725527152072.
It is an arithmetic number, because the mean of its divisors is an integer number (1725527152072).
Almost surely, 23451054304143 is an apocalyptic number.
3451054304143 is a deficient number, since it is larger than the sum of its proper divisors (1).
3451054304143 is an equidigital number, since it uses as much as digits as its factorization.
3451054304143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 172800, while the sum is 37.
Adding to 3451054304143 its reverse (3414034501543), we get a palindrome (6865088805686).
The spelling of 3451054304143 in words is "three trillion, four hundred fifty-one billion, fifty-four million, three hundred four thousand, one hundred forty-three".
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