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345152523413561 is a prime number
BaseRepresentation
bin100111001111010100001010…
…1100011010010100000111001
31200021002020222210200221002212
41032132220111203102200321
5330214434331443213221
63222024514051104505
7132462306201113123
oct11636502543224071
91607066883627085
10345152523413561
119aa813aa3a5156
1232864a558a2135
1311a7898804c4b6
146133685232213
1529d832117eb5b
hex139ea158d2839

345152523413561 has 2 divisors, whose sum is σ = 345152523413562. Its totient is φ = 345152523413560.

The previous prime is 345152523413519. The next prime is 345152523413563. The reversal of 345152523413561 is 165314325251543.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 264474403003561 + 80678120410000 = 16262669^2 + 8982100^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-345152523413561 is a prime.

Together with 345152523413563, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (345152523413563) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 172576261706780 + 172576261706781.

It is an arithmetic number, because the mean of its divisors is an integer number (172576261706781).

Almost surely, 2345152523413561 is an apocalyptic number.

It is an amenable number.

345152523413561 is a deficient number, since it is larger than the sum of its proper divisors (1).

345152523413561 is an equidigital number, since it uses as much as digits as its factorization.

345152523413561 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6480000, while the sum is 50.

The spelling of 345152523413561 in words is "three hundred forty-five trillion, one hundred fifty-two billion, five hundred twenty-three million, four hundred thirteen thousand, five hundred sixty-one".