Base | Representation |
---|---|
bin | 1100110111000111… |
… | …0111000110110111 |
3 | 22220121022002112201 |
4 | 3031301313012313 |
5 | 24032303300210 |
6 | 1330324525331 |
7 | 151360626166 |
oct | 31561670667 |
9 | 8817262481 |
10 | 3452400055 |
11 | 1511876295 |
12 | 804250847 |
13 | 430341790 |
14 | 24a72b3dd |
15 | 15315853a |
hex | cdc771b7 |
3452400055 has 16 divisors (see below), whose sum is σ = 4502504160. Its totient is φ = 2526069888.
The previous prime is 3452400031. The next prime is 3452400059. The reversal of 3452400055 is 5500042543.
It is a cyclic number.
It is not a de Polignac number, because 3452400055 - 29 = 3452399543 is a prime.
It is a super-2 number, since 2×34524000552 = 23838132279528006050, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 3452399996 and 3452400032.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3452400059) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 236557 + ... + 250726.
It is an arithmetic number, because the mean of its divisors is an integer number (281406510).
Almost surely, 23452400055 is an apocalyptic number.
3452400055 is a deficient number, since it is larger than the sum of its proper divisors (1050104105).
3452400055 is a wasteful number, since it uses less digits than its factorization.
3452400055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 487410.
The product of its (nonzero) digits is 12000, while the sum is 28.
The square root of 3452400055 is about 58757.1276952848. The cubic root of 3452400055 is about 1511.3801184098.
Adding to 3452400055 its reverse (5500042543), we get a palindrome (8952442598).
The spelling of 3452400055 in words is "three billion, four hundred fifty-two million, four hundred thousand, fifty-five".
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