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3472442740049 is a prime number
BaseRepresentation
bin110010100001111101101…
…101110100110101010001
3110021221222111122010201012
4302201331231310311101
5423343030320140144
611215115043020305
7505606240200623
oct62417555646521
913257874563635
103472442740049
111119722444978
12480b9606a695
131c25b06b72aa
14c00d2298c13
15604d5e17e9e
hex3287db74d51

3472442740049 has 2 divisors, whose sum is σ = 3472442740050. Its totient is φ = 3472442740048.

The previous prime is 3472442740021. The next prime is 3472442740051. The reversal of 3472442740049 is 9400472442743.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3429015097600 + 43427642449 = 1851760^2 + 208393^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3472442740049 is a prime.

Together with 3472442740051, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 3472442739979 and 3472442740006.

It is not a weakly prime, because it can be changed into another prime (3472442790049) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1736221370024 + 1736221370025.

It is an arithmetic number, because the mean of its divisors is an integer number (1736221370025).

Almost surely, 23472442740049 is an apocalyptic number.

It is an amenable number.

3472442740049 is a deficient number, since it is larger than the sum of its proper divisors (1).

3472442740049 is an equidigital number, since it uses as much as digits as its factorization.

3472442740049 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5419008, while the sum is 50.

The spelling of 3472442740049 in words is "three trillion, four hundred seventy-two billion, four hundred forty-two million, seven hundred forty thousand, forty-nine".