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3474041650663 is a prime number
BaseRepresentation
bin110010100011011101000…
…001001011110111100111
3110022010002221021012201211
4302203131001023313213
5423404314130310123
611215541441132251
7505663663542613
oct62433501136747
913263087235654
103474041650663
11111a372a42101
1248136162a087
131c27a6a2b24c
14c0204788343
156057b49e40d
hex328dd04bde7

3474041650663 has 2 divisors, whose sum is σ = 3474041650664. Its totient is φ = 3474041650662.

The previous prime is 3474041650631. The next prime is 3474041650679. The reversal of 3474041650663 is 3660561404743.

3474041650663 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (3660561404743) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3474041650663 - 25 = 3474041650631 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3474041650063) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1737020825331 + 1737020825332.

It is an arithmetic number, because the mean of its divisors is an integer number (1737020825332).

Almost surely, 23474041650663 is an apocalyptic number.

3474041650663 is a deficient number, since it is larger than the sum of its proper divisors (1).

3474041650663 is an equidigital number, since it uses as much as digits as its factorization.

3474041650663 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4354560, while the sum is 49.

The spelling of 3474041650663 in words is "three trillion, four hundred seventy-four billion, forty-one million, six hundred fifty thousand, six hundred sixty-three".