Base | Representation |
---|---|
bin | 110010100011011101000… |
… | …001001011110111100111 |
3 | 110022010002221021012201211 |
4 | 302203131001023313213 |
5 | 423404314130310123 |
6 | 11215541441132251 |
7 | 505663663542613 |
oct | 62433501136747 |
9 | 13263087235654 |
10 | 3474041650663 |
11 | 111a372a42101 |
12 | 48136162a087 |
13 | 1c27a6a2b24c |
14 | c0204788343 |
15 | 6057b49e40d |
hex | 328dd04bde7 |
3474041650663 has 2 divisors, whose sum is σ = 3474041650664. Its totient is φ = 3474041650662.
The previous prime is 3474041650631. The next prime is 3474041650679. The reversal of 3474041650663 is 3660561404743.
3474041650663 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (3660561404743) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3474041650663 - 25 = 3474041650631 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3474041650063) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1737020825331 + 1737020825332.
It is an arithmetic number, because the mean of its divisors is an integer number (1737020825332).
Almost surely, 23474041650663 is an apocalyptic number.
3474041650663 is a deficient number, since it is larger than the sum of its proper divisors (1).
3474041650663 is an equidigital number, since it uses as much as digits as its factorization.
3474041650663 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4354560, while the sum is 49.
The spelling of 3474041650663 in words is "three trillion, four hundred seventy-four billion, forty-one million, six hundred fifty thousand, six hundred sixty-three".
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