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3477231240061 is a prime number
BaseRepresentation
bin110010100110011011001…
…000100000001101111101
3110022102100020001010211111
4302212123020200031331
5423432332144140221
611221230141122021
7506136013603225
oct62463310401575
913272306033744
103477231240061
11112075a4248a7
12481ab1859311
131c2b94793357
14c0428223085
15606b64e2be1
hex3299b22037d

3477231240061 has 2 divisors, whose sum is σ = 3477231240062. Its totient is φ = 3477231240060.

The previous prime is 3477231240059. The next prime is 3477231240079. The reversal of 3477231240061 is 1600421327743.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3476244651961 + 986588100 = 1864469^2 + 31410^2 .

It is a cyclic number.

It is not a de Polignac number, because 3477231240061 - 21 = 3477231240059 is a prime.

It is a super-2 number, since 2×34772312400612 (a number of 26 digits) contains 22 as substring.

Together with 3477231240059, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 3477231239996 and 3477231240023.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3477231240661) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1738615620030 + 1738615620031.

It is an arithmetic number, because the mean of its divisors is an integer number (1738615620031).

Almost surely, 23477231240061 is an apocalyptic number.

It is an amenable number.

3477231240061 is a deficient number, since it is larger than the sum of its proper divisors (1).

3477231240061 is an equidigital number, since it uses as much as digits as its factorization.

3477231240061 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 169344, while the sum is 40.

The spelling of 3477231240061 in words is "three trillion, four hundred seventy-seven billion, two hundred thirty-one million, two hundred forty thousand, sixty-one".