347940113 has 4 divisors (see below), whose sum is σ = 363067968. Its totient is φ = 332812260.

The previous prime is 347940091. The next prime is 347940121. The reversal of 347940113 is 311049743.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311049743 = 4001 ⋅77743.

It is a cyclic number.

It is not a de Polignac number, because 347940113 - 2⁶ = 347940049 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 347940113.

It is not an unprimeable number, because it can be changed into a prime (347940143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7563893 + ... + 7563938.

It is an arithmetic number, because the mean of its divisors is an integer number (90766992).

Almost surely, 2^347940113 is an apocalyptic number.

It is an amenable number.

347940113 is a deficient number, since it is larger than the sum of its proper divisors (15127855).

347940113 is a wasteful number, since it uses less digits than its factorization.

347940113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15127854.

The product of its (nonzero) digits is 9072, while the sum is 32.

The square root of 347940113 is about 18653.1528970306. The cubic root of 347940113 is about 703.3446149944.

Adding to 347940113 its reverse (311049743), we get a palindrome (658989856).

The spelling of 347940113 in words is "three hundred forty-seven million, nine hundred forty thousand, one hundred thirteen".