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3481116549120 = 213345741923
BaseRepresentation
bin110010101010000010101…
…101110010000000000000
3110022210100222221021220000
4302222002231302000000
5424013311314032440
611223111452520000
7506334212310000
oct62520255620000
913283328837800
103481116549120
1111223735a3021
124827b6a80000
131c33636c94b2
14c06b6240000
1560842660730
hex32a82b72000

3481116549120 has 2800 divisors, whose sum is σ = 15991323099840. Its totient is φ = 721031528448.

The previous prime is 3481116549091. The next prime is 3481116549133. The reversal of 3481116549120 is 219456111843.

3481116549120 is a `hidden beast` number, since 3 + 4 + 81 + 1 + 1 + 6 + 549 + 1 + 20 = 666.

It is a Harshad number since it is a multiple of its sum of digits (45).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 199 ways as a sum of consecutive naturals, for example, 151352893429 + ... + 151352893451.

Almost surely, 23481116549120 is an apocalyptic number.

3481116549120 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 3481116549120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (7995661549920).

3481116549120 is an abundant number, since it is smaller than the sum of its proper divisors (12510206550720).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

3481116549120 is an frugal number, since it uses more digits than its factorization.

3481116549120 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 113 (or 59 counting only the distinct ones).

The product of its (nonzero) digits is 207360, while the sum is 45.

The spelling of 3481116549120 in words is "three trillion, four hundred eighty-one billion, one hundred sixteen million, five hundred forty-nine thousand, one hundred twenty".