Base | Representation |
---|---|
bin | 1101010011110101101101 |
3 | 20120021012011 |
4 | 31103311231 |
5 | 1343123013 |
6 | 202441221 |
7 | 41441254 |
oct | 15236555 |
9 | 6507164 |
10 | 3489133 |
11 | 1a7348a |
12 | 1203211 |
13 | 95219b |
14 | 66b79b |
15 | 48dc3d |
hex | 353d6d |
3489133 has 4 divisors (see below), whose sum is σ = 3512700. Its totient is φ = 3465568.
The previous prime is 3489127. The next prime is 3489173. The reversal of 3489133 is 3319843.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3319843 = 23 ⋅144341.
It can be written as a sum of positive squares in 2 ways, for example, as 887364 + 2601769 = 942^2 + 1613^2 .
It is a cyclic number.
It is not a de Polignac number, because 3489133 - 221 = 1391981 is a prime.
It is a Smith number, since the sum of its digits (31) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.
It is a Duffinian number.
3489133 is a lucky number.
It is a junction number, because it is equal to n+sod(n) for n = 3489095 and 3489104.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3489173) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11560 + ... + 11857.
It is an arithmetic number, because the mean of its divisors is an integer number (878175).
Almost surely, 23489133 is an apocalyptic number.
It is an amenable number.
3489133 is a deficient number, since it is larger than the sum of its proper divisors (23567).
3489133 is a wasteful number, since it uses less digits than its factorization.
3489133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23566.
The product of its digits is 7776, while the sum is 31.
The square root of 3489133 is about 1867.9221075837. The cubic root of 3489133 is about 151.6721494348.
It can be divided in two parts, 34891 and 33, that multiplied together give a triangular number (1151403 = T1517).
The spelling of 3489133 in words is "three million, four hundred eighty-nine thousand, one hundred thirty-three".
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