Base | Representation |
---|---|
bin | 1111111001000100001011… |
… | …00010110001000111100111 |
3 | 11120201210222101220212212101 |
4 | 13330202011202301013213 |
5 | 14040024100131412241 |
6 | 202154003015432531 |
7 | 10234525540216504 |
oct | 774420542610747 |
9 | 146653871825771 |
10 | 34946094404071 |
11 | 10153612280534 |
12 | 3b04954385747 |
13 | 1666530576796 |
14 | 88b5858244ab |
15 | 409064d2be31 |
hex | 1fc8858b11e7 |
34946094404071 has 2 divisors, whose sum is σ = 34946094404072. Its totient is φ = 34946094404070.
The previous prime is 34946094404041. The next prime is 34946094404083. The reversal of 34946094404071 is 17040449064943.
It is a strong prime.
It is an emirp because it is prime and its reverse (17040449064943) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 34946094404071 - 29 = 34946094403559 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (34946094404041) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17473047202035 + 17473047202036.
It is an arithmetic number, because the mean of its divisors is an integer number (17473047202036).
Almost surely, 234946094404071 is an apocalyptic number.
34946094404071 is a deficient number, since it is larger than the sum of its proper divisors (1).
34946094404071 is an equidigital number, since it uses as much as digits as its factorization.
34946094404071 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10450944, while the sum is 55.
The spelling of 34946094404071 in words is "thirty-four trillion, nine hundred forty-six billion, ninety-four million, four hundred four thousand, seventy-one".
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