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349464541 is a prime number
BaseRepresentation
bin10100110101000…
…110011111011101
3220100120122020011
4110311012133131
51203430331131
654402123221
711442254026
oct2465063735
9810518204
10349464541
1116a299978
1299050511
135752956a
14345abc4d
1520a300b1
hex14d467dd

349464541 has 2 divisors, whose sum is σ = 349464542. Its totient is φ = 349464540.

The previous prime is 349464523. The next prime is 349464551. The reversal of 349464541 is 145464943.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 291384900 + 58079641 = 17070^2 + 7621^2 .

It is a cyclic number.

It is not a de Polignac number, because 349464541 - 211 = 349462493 is a prime.

It is a Chen prime.

It is equal to p18776155 and since 349464541 and 18776155 have the same sum of digits, it is a Honaker prime.

It is a junction number, because it is equal to n+sod(n) for n = 349464494 and 349464503.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (349464551) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 174732270 + 174732271.

It is an arithmetic number, because the mean of its divisors is an integer number (174732271).

Almost surely, 2349464541 is an apocalyptic number.

It is an amenable number.

349464541 is a deficient number, since it is larger than the sum of its proper divisors (1).

349464541 is an equidigital number, since it uses as much as digits as its factorization.

349464541 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 207360, while the sum is 40.

The square root of 349464541 is about 18693.9707125051. The cubic root of 349464541 is about 704.3703050611.

The spelling of 349464541 in words is "three hundred forty-nine million, four hundred sixty-four thousand, five hundred forty-one".