34974893 has 4 divisors (see below), whose sum is σ = 34987740. Its totient is φ = 34962048.

The previous prime is 34974869. The next prime is 34974923. The reversal of 34974893 is 39847943.

34974893 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 39847943 = 29 ⋅1374067.

It can be written as a sum of positive squares in 2 ways, for example, as 13053769 + 21921124 = 3613^2 + 4682^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-34974893 is a prime.

It is a super-2 number, since 2×34974893² = 2446486280722898, which contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (34974803) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 548 + ... + 8381.

It is an arithmetic number, because the mean of its divisors is an integer number (8746935).

Almost surely, 2^34974893 is an apocalyptic number.

It is an amenable number.

34974893 is a deficient number, since it is larger than the sum of its proper divisors (12847).

34974893 is an equidigital number, since it uses as much as digits as its factorization.

34974893 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12846.

The product of its digits is 653184, while the sum is 47.

The square root of 34974893 is about 5913.9574736381. The cubic root of 34974893 is about 327.0283964404.

The spelling of 34974893 in words is "thirty-four million, nine hundred seventy-four thousand, eight hundred ninety-three".