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350025314042 = 2175012657021
BaseRepresentation
bin1010001011111110010…
…00100110111011111010
31020110110212101021201002
411011333020212323322
521213322440022132
6424444401125002
734200645036065
oct5057710467372
91213425337632
10350025314042
1112549918a148
1257a06929762
1327012bc2751
1412d26d818dc
1591893a4262
hex517f226efa

350025314042 has 4 divisors (see below), whose sum is σ = 525037971066. Its totient is φ = 175012657020.

The previous prime is 350025314027. The next prime is 350025314059. The reversal of 350025314042 is 240413520053.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 347617547281 + 2407766761 = 589591^2 + 49069^2 .

It is a junction number, because it is equal to n+sod(n) for n = 350025313996 and 350025314014.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 87506328509 + ... + 87506328512.

Almost surely, 2350025314042 is an apocalyptic number.

350025314042 is a deficient number, since it is larger than the sum of its proper divisors (175012657024).

350025314042 is a wasteful number, since it uses less digits than its factorization.

350025314042 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 175012657023.

The product of its (nonzero) digits is 14400, while the sum is 29.

Adding to 350025314042 its reverse (240413520053), we get a palindrome (590438834095).

The spelling of 350025314042 in words is "three hundred fifty billion, twenty-five million, three hundred fourteen thousand, forty-two".

Divisors: 1 2 175012657021 350025314042