3500402149 has 2 divisors, whose sum is σ = 3500402150. Its totient is φ = 3500402148.

The previous prime is 3500402117. The next prime is 3500402201. The reversal of 3500402149 is 9412040053.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3481826049 + 18576100 = 59007^2 + 4310^2 .

It is a cyclic number.

It is not a de Polignac number, because 3500402149 - 2⁵ = 3500402117 is a prime.

It is a super-4 number, since 4×3500402149⁴ (a number of 39 digits) contains 4444 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3500402849) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1750201074 + 1750201075.

It is an arithmetic number, because the mean of its divisors is an integer number (1750201075).

Almost surely, 2^3500402149 is an apocalyptic number.

It is an amenable number.

3500402149 is a deficient number, since it is larger than the sum of its proper divisors (1).

3500402149 is an equidigital number, since it uses as much as digits as its factorization.

3500402149 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4320, while the sum is 28.

The square root of 3500402149 is about 59164.1965127559. The cubic root of 3500402149 is about 1518.3526342450.

The spelling of 3500402149 in words is "three billion, five hundred million, four hundred two thousand, one hundred forty-nine".