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350131051141 is a prime number
BaseRepresentation
bin1010001100001010110…
…11111101101010000101
31020110202020100021201221
411012011123331222011
521214032022114031
6424503055320341
734203400554364
oct5060533755205
91213666307657
10350131051141
11125542939a83
1257a362200b1
132702ba94691
1412d370277db
1591937dda11
hex51856fda85

350131051141 has 2 divisors, whose sum is σ = 350131051142. Its totient is φ = 350131051140.

The previous prime is 350131051139. The next prime is 350131051181. The reversal of 350131051141 is 141150131053.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 340419737025 + 9711314116 = 583455^2 + 98546^2 .

It is an emirp because it is prime and its reverse (141150131053) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 350131051141 - 21 = 350131051139 is a prime.

Together with 350131051139, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (350131051181) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 175065525570 + 175065525571.

It is an arithmetic number, because the mean of its divisors is an integer number (175065525571).

Almost surely, 2350131051141 is an apocalyptic number.

It is an amenable number.

350131051141 is a deficient number, since it is larger than the sum of its proper divisors (1).

350131051141 is an equidigital number, since it uses as much as digits as its factorization.

350131051141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 900, while the sum is 25.

Adding to 350131051141 its reverse (141150131053), we get a palindrome (491281182194).

The spelling of 350131051141 in words is "three hundred fifty billion, one hundred thirty-one million, fifty-one thousand, one hundred forty-one".