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350218439141 is a prime number
BaseRepresentation
bin1010001100010101010…
…01010100100111100101
31020110222022210001112112
411012022221110213211
521214221410023031
6424515500330405
734205511421034
oct5061251244745
91213868701475
10350218439141
111255881a696a
1257a5b543a05
1327043c1075c
1412d4489471b
15919b30162b
hex518aa549e5

350218439141 has 2 divisors, whose sum is σ = 350218439142. Its totient is φ = 350218439140.

The previous prime is 350218439059. The next prime is 350218439143. The reversal of 350218439141 is 141934812053.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 342570237025 + 7648202116 = 585295^2 + 87454^2 .

It is a cyclic number.

It is not a de Polignac number, because 350218439141 - 210 = 350218438117 is a prime.

It is a super-2 number, since 2×3502184391412 (a number of 24 digits) contains 22 as substring.

Together with 350218439143, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (350218439143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 175109219570 + 175109219571.

It is an arithmetic number, because the mean of its divisors is an integer number (175109219571).

Almost surely, 2350218439141 is an apocalyptic number.

It is an amenable number.

350218439141 is a deficient number, since it is larger than the sum of its proper divisors (1).

350218439141 is an equidigital number, since it uses as much as digits as its factorization.

350218439141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 103680, while the sum is 41.

The spelling of 350218439141 in words is "three hundred fifty billion, two hundred eighteen million, four hundred thirty-nine thousand, one hundred forty-one".