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3504541429981 is a prime number
BaseRepresentation
bin110010111111110110111…
…100100111000011011101
3110102000211111222112110001
4302333312330213003131
5424404300101224411
611241544125214301
7511123542436204
oct62776674470335
913360744875401
103504541429981
1111312a4301799
12487253a01391
131c56277cbb47
14c189932c23b
1561263deadc1
hex32ff6f270dd

3504541429981 has 2 divisors, whose sum is σ = 3504541429982. Its totient is φ = 3504541429980.

The previous prime is 3504541429979. The next prime is 3504541429999. The reversal of 3504541429981 is 1899241454053.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3438817904025 + 65723525956 = 1854405^2 + 256366^2 .

It is a cyclic number.

It is not a de Polignac number, because 3504541429981 - 21 = 3504541429979 is a prime.

It is a super-2 number, since 2×35045414299812 (a number of 26 digits) contains 22 as substring.

Together with 3504541429979, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3504541429381) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1752270714990 + 1752270714991.

It is an arithmetic number, because the mean of its divisors is an integer number (1752270714991).

Almost surely, 23504541429981 is an apocalyptic number.

It is an amenable number.

3504541429981 is a deficient number, since it is larger than the sum of its proper divisors (1).

3504541429981 is an equidigital number, since it uses as much as digits as its factorization.

3504541429981 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6220800, while the sum is 55.

The spelling of 3504541429981 in words is "three trillion, five hundred four billion, five hundred forty-one million, four hundred twenty-nine thousand, nine hundred eighty-one".