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350524400022149 is a prime number
BaseRepresentation
bin100111110110011001101001…
…0010110010011001010000101
31200222002210202010021010011112
41033230303102112103022011
5331420442432401202044
63241300404130014405
7133555360253644433
oct11754632226231205
91628083663233145
10350524400022149
11a1762621729871
1233391b88417405
13120784030c0592
14627b685a6bd53
152a7ce262ad09e
hex13eccd2593285

350524400022149 has 2 divisors, whose sum is σ = 350524400022150. Its totient is φ = 350524400022148.

The previous prime is 350524400022133. The next prime is 350524400022151. The reversal of 350524400022149 is 941220004425053.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 308595343201924 + 41929056820225 = 17566882^2 + 6475265^2 .

It is an emirp because it is prime and its reverse (941220004425053) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 350524400022149 - 24 = 350524400022133 is a prime.

Together with 350524400022151, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (350524400072149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 175262200011074 + 175262200011075.

It is an arithmetic number, because the mean of its divisors is an integer number (175262200011075).

Almost surely, 2350524400022149 is an apocalyptic number.

It is an amenable number.

350524400022149 is a deficient number, since it is larger than the sum of its proper divisors (1).

350524400022149 is an equidigital number, since it uses as much as digits as its factorization.

350524400022149 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 345600, while the sum is 41.

The spelling of 350524400022149 in words is "three hundred fifty trillion, five hundred twenty-four billion, four hundred million, twenty-two thousand, one hundred forty-nine".