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35113204039981 is a prime number
BaseRepresentation
bin1111111101111011011100…
…00011011100000100101101
311121022210022120011221211211
413332331232003130010231
514100243320213234411
6202402441103114421
710252562633536264
oct776755603340455
9147283276157754
1035113204039981
1110208476310351
123b31210ba2a11
131679212754a52
148956b96735db
1540d595a3d221
hex1fef6e0dc12d

35113204039981 has 2 divisors, whose sum is σ = 35113204039982. Its totient is φ = 35113204039980.

The previous prime is 35113204039933. The next prime is 35113204040003. The reversal of 35113204039981 is 18993040231153.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 33373047317481 + 1740156722500 = 5776941^2 + 1319150^2 .

It is an emirp because it is prime and its reverse (18993040231153) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-35113204039981 is a prime.

It is a super-2 number, since 2×351132040399812 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (35113204039931) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17556602019990 + 17556602019991.

It is an arithmetic number, because the mean of its divisors is an integer number (17556602019991).

Almost surely, 235113204039981 is an apocalyptic number.

It is an amenable number.

35113204039981 is a deficient number, since it is larger than the sum of its proper divisors (1).

35113204039981 is an equidigital number, since it uses as much as digits as its factorization.

35113204039981 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 699840, while the sum is 49.

The spelling of 35113204039981 in words is "thirty-five trillion, one hundred thirteen billion, two hundred four million, thirty-nine thousand, nine hundred eighty-one".