Base | Representation |
---|---|
bin | 1111111101111011011100… |
… | …00011011100100101000010 |
3 | 11121022210022120012001200110 |
4 | 13332331232003130211002 |
5 | 14100243320213321200 |
6 | 202402441103132150 |
7 | 10252562633545311 |
oct | 776755603344502 |
9 | 147283276161613 |
10 | 35113204042050 |
11 | 10208476311962 |
12 | 3b31210ba4056 |
13 | 1679212755984 |
14 | 8956b9674278 |
15 | 40d595a3db50 |
hex | 1fef6e0dc942 |
35113204042050 has 48 divisors (see below), whose sum is σ = 89434279714752. Its totient is φ = 9110452939200.
The previous prime is 35113204041997. The next prime is 35113204042073. The reversal of 35113204042050 is 5024040231153.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 35113204041999 and 35113204042017.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3163346166 + ... + 3163357265.
It is an arithmetic number, because the mean of its divisors is an integer number (1863214160724).
Almost surely, 235113204042050 is an apocalyptic number.
35113204042050 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
35113204042050 is an abundant number, since it is smaller than the sum of its proper divisors (54321075672702).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
35113204042050 is a wasteful number, since it uses less digits than its factorization.
35113204042050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6326703483 (or 6326703478 counting only the distinct ones).
The product of its (nonzero) digits is 14400, while the sum is 30.
The spelling of 35113204042050 in words is "thirty-five trillion, one hundred thirteen billion, two hundred four million, forty-two thousand, fifty".
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