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351201454142 = 27113001759923
BaseRepresentation
bin1010001110001010011…
…11001110100000111110
31020120111211111101121112
411013011033032200332
521223230033013032
6425201214002022
734242046051010
oct5070517164076
91216454441545
10351201454142
11125a42079660
12580947a6312
132716c781936
1412dd92601b0
15920777a1b2
hex51c53ce83e

351201454142 has 32 divisors (see below), whose sum is σ = 657012052224. Its totient is φ = 136785960000.

The previous prime is 351201454117. The next prime is 351201454147. The reversal of 351201454142 is 241454102153.

It is a super-2 number, since 2×3512014541422 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 351201454099 and 351201454108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (351201454147) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 82193 + ... + 842115.

It is an arithmetic number, because the mean of its divisors is an integer number (20531626632).

Almost surely, 2351201454142 is an apocalyptic number.

351201454142 is a deficient number, since it is larger than the sum of its proper divisors (305810598082).

351201454142 is a wasteful number, since it uses less digits than its factorization.

351201454142 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 762944.

The product of its (nonzero) digits is 19200, while the sum is 32.

Adding to 351201454142 its reverse (241454102153), we get a palindrome (592655556295).

The spelling of 351201454142 in words is "three hundred fifty-one billion, two hundred one million, four hundred fifty-four thousand, one hundred forty-two".

Divisors: 1 2 7 11 14 22 77 154 3001 6002 21007 33011 42014 66022 231077 462154 759923 1519846 5319461 8359153 10638922 16718306 58514071 117028142 2280528923 4561057846 15963702461 25085818153 31927404922 50171636306 175600727071 351201454142