3513125401 has 4 divisors (see below), whose sum is σ = 3513244032. Its totient is φ = 3513006772.

The previous prime is 3513125267. The next prime is 3513125417. The reversal of 3513125401 is 1045213153.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3513125401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3513125461) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26256 + ... + 87838.

It is an arithmetic number, because the mean of its divisors is an integer number (878311008).

Almost surely, 2^3513125401 is an apocalyptic number.

It is an amenable number.

3513125401 is a deficient number, since it is larger than the sum of its proper divisors (118631).

3513125401 is an equidigital number, since it uses as much as digits as its factorization.

3513125401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 118630.

The product of its (nonzero) digits is 1800, while the sum is 25.

The square root of 3513125401 is about 59271.6239106033. The cubic root of 3513125401 is about 1520.1900444800.

Adding to 3513125401 its reverse (1045213153), we get a palindrome (4558338554).

The spelling of 3513125401 in words is "three billion, five hundred thirteen million, one hundred twenty-five thousand, four hundred one".