Search a number
-
+
35134044043153 = 1123138869739301
BaseRepresentation
bin1111111110100010010000…
…01101101111011110010001
311121101210002221022210211011
413333101020031233132101
514101114010233340103
6202420205040450521
710254231235620106
oct777211015573621
9147353087283734
1035134044043153
111021629aa13170
123b35268319a41
13167b18417a683
148966d5338aad
1540ddb53d3d6d
hex1ff44836f791

35134044043153 has 8 divisors (see below), whose sum is σ = 39994484918976. Its totient is φ = 30551342646000.

The previous prime is 35134044043127. The next prime is 35134044043157.

35134044043153 is nontrivially palindromic in base 10.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 35134044043153 - 29 = 35134044042641 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (35134044043157) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 69434869398 + ... + 69434869903.

It is an arithmetic number, because the mean of its divisors is an integer number (4999310614872).

Almost surely, 235134044043153 is an apocalyptic number.

It is an amenable number.

35134044043153 is a deficient number, since it is larger than the sum of its proper divisors (4860440875823).

35134044043153 is a wasteful number, since it uses less digits than its factorization.

35134044043153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 138869739335.

The product of its (nonzero) digits is 518400, while the sum is 40.

It can be divided in two parts, 3513404 and 4043153, that added together give a palindrome (7556557).

The spelling of 35134044043153 in words is "thirty-five trillion, one hundred thirty-four billion, forty-four million, forty-three thousand, one hundred fifty-three".

Divisors: 1 11 23 253 138869739301 1527567132311 3194004003923 35134044043153