Base | Representation |
---|---|
bin | 110011001000010000001… |
… | …100101100110111101111 |
3 | 110102220002200121222222222 |
4 | 303020100030230313233 |
5 | 430031230040404403 |
6 | 11250034353425555 |
7 | 511563111562202 |
oct | 63102014546757 |
9 | 13386080558888 |
10 | 3513555013103 |
11 | 11350aa230143 |
12 | 488b4a56b2bb |
13 | 1c6433026895 |
14 | c20b247b939 |
15 | 615e03ac338 |
hex | 3321032cdef |
3513555013103 has 4 divisors (see below), whose sum is σ = 3513649604880. Its totient is φ = 3513460421328.
The previous prime is 3513555013099. The next prime is 3513555013139. The reversal of 3513555013103 is 3013105553153.
It is a happy number.
3513555013103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3513555013103 - 22 = 3513555013099 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3513555013403) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47240150 + ... + 47314467.
It is an arithmetic number, because the mean of its divisors is an integer number (878412401220).
Almost surely, 23513555013103 is an apocalyptic number.
3513555013103 is a deficient number, since it is larger than the sum of its proper divisors (94591777).
3513555013103 is an equidigital number, since it uses as much as digits as its factorization.
3513555013103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 94591776.
The product of its (nonzero) digits is 50625, while the sum is 35.
The spelling of 3513555013103 in words is "three trillion, five hundred thirteen billion, five hundred fifty-five million, thirteen thousand, one hundred three".
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