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35140000301 = 710091497473
BaseRepresentation
bin100000101110100000…
…011101101000101101
310100200222002222020122
4200232200131220231
51033431320002201
624050524054325
72352542034320
oct405640355055
9110628088218
1035140000301
11139a268336a
1269883943a5
1334102311b3
1419b4d507b7
15da9ed6e1b
hex82e81da2d

35140000301 has 8 divisors (see below), whose sum is σ = 40164060864. Its totient is φ = 30116954880.

The previous prime is 35140000271. The next prime is 35140000309. The reversal of 35140000301 is 10300004153.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-35140000301 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 35140000301.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (35140000309) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 178100 + ... + 319373.

It is an arithmetic number, because the mean of its divisors is an integer number (5020507608).

Almost surely, 235140000301 is an apocalyptic number.

It is an amenable number.

35140000301 is a deficient number, since it is larger than the sum of its proper divisors (5024060563).

35140000301 is a wasteful number, since it uses less digits than its factorization.

35140000301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 507571.

The product of its (nonzero) digits is 180, while the sum is 17.

Adding to 35140000301 its reverse (10300004153), we get a palindrome (45440004454).

The spelling of 35140000301 in words is "thirty-five billion, one hundred forty million, three hundred one", and thus it is an aban number.

Divisors: 1 7 10091 70637 497473 3482311 5020000043 35140000301