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3514339920061 is a prime number
BaseRepresentation
bin110011001000111110111…
…110111000100010111101
3110102222010101120101221001
4303020332332320202331
5430034332004420221
611250244313010301
7511621422304525
oct63107676704275
913388111511831
103514339920061
1111354722a2383
124891293b3991
131c6529823979
14c21487d8685
1561639252391
hex3323efb88bd

3514339920061 has 2 divisors, whose sum is σ = 3514339920062. Its totient is φ = 3514339920060.

The previous prime is 3514339920059. The next prime is 3514339920071. The reversal of 3514339920061 is 1600299334153.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3472982596836 + 41357323225 = 1863594^2 + 203365^2 .

It is a cyclic number.

It is not a de Polignac number, because 3514339920061 - 21 = 3514339920059 is a prime.

Together with 3514339920059, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 3514339919993 and 3514339920020.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3514339920011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1757169960030 + 1757169960031.

It is an arithmetic number, because the mean of its divisors is an integer number (1757169960031).

Almost surely, 23514339920061 is an apocalyptic number.

It is an amenable number.

3514339920061 is a deficient number, since it is larger than the sum of its proper divisors (1).

3514339920061 is an equidigital number, since it uses as much as digits as its factorization.

3514339920061 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 524880, while the sum is 46.

The spelling of 3514339920061 in words is "three trillion, five hundred fourteen billion, three hundred thirty-nine million, nine hundred twenty thousand, sixty-one".