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352015114413 = 3117338371471
BaseRepresentation
bin1010001111101011011…
…11000110000010101101
31020122121112112121200010
411013311233012002231
521231411332130123
6425414041323433
734301156050254
oct5076557060255
91218545477603
10352015114413
1112631a39a666
1258281196579
132726c208411
141307534379b
159253dee993
hex51f5bc60ad

352015114413 has 4 divisors (see below), whose sum is σ = 469353485888. Its totient is φ = 234676742940.

The previous prime is 352015114397. The next prime is 352015114421. The reversal of 352015114413 is 314411510253.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 352015114413 - 24 = 352015114397 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (352015114483) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 58669185733 + ... + 58669185738.

It is an arithmetic number, because the mean of its divisors is an integer number (117338371472).

Almost surely, 2352015114413 is an apocalyptic number.

It is an amenable number.

352015114413 is a deficient number, since it is larger than the sum of its proper divisors (117338371475).

352015114413 is a wasteful number, since it uses less digits than its factorization.

352015114413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 117338371474.

The product of its (nonzero) digits is 7200, while the sum is 30.

Adding to 352015114413 its reverse (314411510253), we get a palindrome (666426624666).

The spelling of 352015114413 in words is "three hundred fifty-two billion, fifteen million, one hundred fourteen thousand, four hundred thirteen".

Divisors: 1 3 117338371471 352015114413