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352121520133 is a prime number
BaseRepresentation
bin1010001111111000001…
…01000000000000000101
31020122212221202120212201
411013330011000000011
521232121102121013
6425432402114501
734303620352105
oct5077405000005
91218787676781
10352121520133
11126374466879
12582b094ba31
1327288282796
1413085521205
15925d41c3dd
hex51fc140005

352121520133 has 2 divisors, whose sum is σ = 352121520134. Its totient is φ = 352121520132.

The previous prime is 352121520097. The next prime is 352121520137. The reversal of 352121520133 is 331025121253.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 234224057089 + 117897463044 = 483967^2 + 343362^2 .

It is a cyclic number.

It is not a de Polignac number, because 352121520133 - 237 = 214682566661 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (352121520137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 176060760066 + 176060760067.

It is an arithmetic number, because the mean of its divisors is an integer number (176060760067).

Almost surely, 2352121520133 is an apocalyptic number.

It is an amenable number.

352121520133 is a deficient number, since it is larger than the sum of its proper divisors (1).

352121520133 is an equidigital number, since it uses as much as digits as its factorization.

352121520133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5400, while the sum is 28.

Adding to 352121520133 its reverse (331025121253), we get a palindrome (683146641386).

The spelling of 352121520133 in words is "three hundred fifty-two billion, one hundred twenty-one million, five hundred twenty thousand, one hundred thirty-three".