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3532003054141 is a prime number
BaseRepresentation
bin110011011001011011110…
…010011001001000111101
3110111122201100212120210011
4303121123302121020331
5430332020240213031
611302325123143221
7513115220414332
oct63313362311075
913448640776704
103532003054141
111141a06710451
12490638814b11
131c80b30192b3
14c2d425b6989
1561d1ec686b1
hex3365bc9923d

3532003054141 has 2 divisors, whose sum is σ = 3532003054142. Its totient is φ = 3532003054140.

The previous prime is 3532003054123. The next prime is 3532003054147. The reversal of 3532003054141 is 1414503002353.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3399782822500 + 132220231641 = 1843850^2 + 363621^2 .

It is a cyclic number.

It is not a de Polignac number, because 3532003054141 - 25 = 3532003054109 is a prime.

It is a super-2 number, since 2×35320030541412 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3532003054147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1766001527070 + 1766001527071.

It is an arithmetic number, because the mean of its divisors is an integer number (1766001527071).

Almost surely, 23532003054141 is an apocalyptic number.

It is an amenable number.

3532003054141 is a deficient number, since it is larger than the sum of its proper divisors (1).

3532003054141 is an equidigital number, since it uses as much as digits as its factorization.

3532003054141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 3532003054141 its reverse (1414503002353), we get a palindrome (4946506056494).

The spelling of 3532003054141 in words is "three trillion, five hundred thirty-two billion, three million, fifty-four thousand, one hundred forty-one".