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353200315141 is a prime number
BaseRepresentation
bin1010010001111000110…
…00010001101100000101
31020202200010201001102101
411020330120101230011
521241323240041031
6430131420312101
734342430100052
oct5107430215405
91222603631371
10353200315141
111268784084a3
12585520a2631
13273ca91a71b
1413148900029
1592c2eb5361
hex523c611b05

353200315141 has 2 divisors, whose sum is σ = 353200315142. Its totient is φ = 353200315140.

The previous prime is 353200315109. The next prime is 353200315201. The reversal of 353200315141 is 141513002353.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 233051424516 + 120148890625 = 482754^2 + 346625^2 .

It is an emirp because it is prime and its reverse (141513002353) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 353200315141 - 25 = 353200315109 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (353200315241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 176600157570 + 176600157571.

It is an arithmetic number, because the mean of its divisors is an integer number (176600157571).

Almost surely, 2353200315141 is an apocalyptic number.

It is an amenable number.

353200315141 is a deficient number, since it is larger than the sum of its proper divisors (1).

353200315141 is an equidigital number, since it uses as much as digits as its factorization.

353200315141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5400, while the sum is 28.

Adding to 353200315141 its reverse (141513002353), we get a palindrome (494713317494).

The spelling of 353200315141 in words is "three hundred fifty-three billion, two hundred million, three hundred fifteen thousand, one hundred forty-one".