Base | Representation |
---|---|
bin | 1101100000010010011111 |
3 | 20122212010211 |
4 | 31200102133 |
5 | 1401241002 |
6 | 203513251 |
7 | 42043033 |
oct | 15402237 |
9 | 6585124 |
10 | 3540127 |
11 | 1aa8828 |
12 | 1228827 |
13 | 96c466 |
14 | 6821c3 |
15 | 49ddd7 |
hex | 36049f |
3540127 has 2 divisors, whose sum is σ = 3540128. Its totient is φ = 3540126.
The previous prime is 3540109. The next prime is 3540133. The reversal of 3540127 is 7210453.
3540127 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (7210453) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3540127 - 219 = 3015839 is a prime.
It is a super-2 number, since 2×35401272 = 25064998352258, which contains 22 as substring.
It is a Chen prime.
It is an Ulam number.
3540127 is a lucky number.
It is a junction number, because it is equal to n+sod(n) for n = 3540098 and 3540107.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3540157) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1770063 + 1770064.
It is an arithmetic number, because the mean of its divisors is an integer number (1770064).
Almost surely, 23540127 is an apocalyptic number.
3540127 is a deficient number, since it is larger than the sum of its proper divisors (1).
3540127 is an equidigital number, since it uses as much as digits as its factorization.
3540127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 840, while the sum is 22.
The square root of 3540127 is about 1881.5225217892. The cubic root of 3540127 is about 152.4074794886.
The spelling of 3540127 in words is "three million, five hundred forty thousand, one hundred twenty-seven".
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