Base | Representation |
---|---|
bin | 110011100001011001100… |
… | …011100100110101100111 |
3 | 110112110210101220101121002 |
4 | 303201121203210311213 |
5 | 431002024210100210 |
6 | 11310301520543515 |
7 | 513540160422626 |
oct | 63413143446547 |
9 | 13473711811532 |
10 | 3540555550055 |
11 | 11455a5340197 |
12 | 492224a81b9b |
13 | 1c8b46b64974 |
14 | c35143bd6bd |
15 | 621709eb4a5 |
hex | 338598e4d67 |
3540555550055 has 4 divisors (see below), whose sum is σ = 4248666660072. Its totient is φ = 2832444440040.
The previous prime is 3540555550013. The next prime is 3540555550073. The reversal of 3540555550055 is 5500555550453.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 3540555550055 - 26 = 3540555549991 is a prime.
It is a super-2 number, since 2×35405555500552 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 3540555549991 and 3540555550009.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 354055555001 + ... + 354055555010.
It is an arithmetic number, because the mean of its divisors is an integer number (1062166665018).
Almost surely, 23540555550055 is an apocalyptic number.
3540555550055 is a deficient number, since it is larger than the sum of its proper divisors (708111110017).
3540555550055 is an equidigital number, since it uses as much as digits as its factorization.
3540555550055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 708111110016.
The product of its (nonzero) digits is 4687500, while the sum is 47.
The spelling of 3540555550055 in words is "three trillion, five hundred forty billion, five hundred fifty-five million, five hundred fifty thousand, fifty-five".
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