35408113 has 4 divisors (see below), whose sum is σ = 38131828. Its totient is φ = 32684400.

The previous prime is 35408099. The next prime is 35408117. The reversal of 35408113 is 31180453.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 31180453 = 761 ⋅40973.

It can be written as a sum of positive squares in 2 ways, for example, as 7656289 + 27751824 = 2767^2 + 5268^2 .

It is a cyclic number.

It is not a de Polignac number, because 35408113 - 2⁹ = 35407601 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (35408117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1361838 + ... + 1361863.

It is an arithmetic number, because the mean of its divisors is an integer number (9532957).

Almost surely, 2^35408113 is an apocalyptic number.

It is an amenable number.

35408113 is a deficient number, since it is larger than the sum of its proper divisors (2723715).

35408113 is a wasteful number, since it uses less digits than its factorization.

35408113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2723714.

The product of its (nonzero) digits is 1440, while the sum is 25.

The square root of 35408113 is about 5950.4716619777. The cubic root of 35408113 is about 328.3731160764.

Adding to 35408113 its reverse (31180453), we get a palindrome (66588566).

The spelling of 35408113 in words is "thirty-five million, four hundred eight thousand, one hundred thirteen".