3540998057 has 2 divisors, whose sum is σ = 3540998058. Its totient is φ = 3540998056.

The previous prime is 3540998053. The next prime is 3540998059. The reversal of 3540998057 is 7508990453.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2360113561 + 1180884496 = 48581^2 + 34364^2 .

It is a cyclic number.

It is not a de Polignac number, because 3540998057 - 2² = 3540998053 is a prime.

Together with 3540998059, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 3540997996 and 3540998014.

It is not a weakly prime, because it can be changed into another prime (3540998053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1770499028 + 1770499029.

It is an arithmetic number, because the mean of its divisors is an integer number (1770499029).

Almost surely, 2^3540998057 is an apocalyptic number.

It is an amenable number.

3540998057 is a deficient number, since it is larger than the sum of its proper divisors (1).

3540998057 is an equidigital number, since it uses as much as digits as its factorization.

3540998057 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1360800, while the sum is 50.

The square root of 3540998057 is about 59506.2858612433. The cubic root of 3540998057 is about 1524.1997854256.

The spelling of 3540998057 in words is "three billion, five hundred forty million, nine hundred ninety-eight thousand, fifty-seven".