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354131121131477 is a prime number
BaseRepresentation
bin101000010000101001001001…
…1101011011100111111010101
31201102212121022201100011210222
41100201102103223130333111
5332404041014002201402
63253101331404324125
7134410062211355504
oct12041222353347725
91642777281304728
10354131121131477
11a292318a776a48
1233874b97b43645
131227a562b67141
1463640756c883b
152ae1b6a9497a2
hex1421493adcfd5

354131121131477 has 2 divisors, whose sum is σ = 354131121131478. Its totient is φ = 354131121131476.

The previous prime is 354131121131423. The next prime is 354131121131509. The reversal of 354131121131477 is 774131121131453.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 204058967976241 + 150072153155236 = 14284921^2 + 12250394^2 .

It is an emirp because it is prime and its reverse (774131121131453) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-354131121131477 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (354131126131477) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 177065560565738 + 177065560565739.

It is an arithmetic number, because the mean of its divisors is an integer number (177065560565739).

Almost surely, 2354131121131477 is an apocalyptic number.

It is an amenable number.

354131121131477 is a deficient number, since it is larger than the sum of its proper divisors (1).

354131121131477 is an equidigital number, since it uses as much as digits as its factorization.

354131121131477 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 211680, while the sum is 44.

The spelling of 354131121131477 in words is "three hundred fifty-four trillion, one hundred thirty-one billion, one hundred twenty-one million, one hundred thirty-one thousand, four hundred seventy-seven".