Base | Representation |
---|---|
bin | 110011100010110110101… |
… | …010011001110010001111 |
3 | 110112121211021012210221001 |
4 | 303202312222121302033 |
5 | 431013224102332004 |
6 | 11311120521321131 |
7 | 513623656001155 |
oct | 63426652316217 |
9 | 13477737183831 |
10 | 3542117620879 |
11 | 1146227066112 |
12 | 4925a00361a7 |
13 | 1c903567a626 |
14 | c3621a3d3d5 |
15 | 62212c071a4 |
hex | 338b6a99c8f |
3542117620879 has 2 divisors, whose sum is σ = 3542117620880. Its totient is φ = 3542117620878.
The previous prime is 3542117620843. The next prime is 3542117620991. The reversal of 3542117620879 is 9780267112453.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3542117620879 - 27 = 3542117620751 is a prime.
It is a super-3 number, since 3×35421176208793 (a number of 39 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3542117620579) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1771058810439 + 1771058810440.
It is an arithmetic number, because the mean of its divisors is an integer number (1771058810440).
It is a 1-persistent number, because it is pandigital, but 2⋅3542117620879 = 7084235241758 is not.
Almost surely, 23542117620879 is an apocalyptic number.
3542117620879 is a deficient number, since it is larger than the sum of its proper divisors (1).
3542117620879 is an equidigital number, since it uses as much as digits as its factorization.
3542117620879 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5080320, while the sum is 55.
The spelling of 3542117620879 in words is "three trillion, five hundred forty-two billion, one hundred seventeen million, six hundred twenty thousand, eight hundred seventy-nine".
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