35421200212453 has 4 divisors (see below), whose sum is σ = 38641309322688. Its totient is φ = 32201091102220.

The previous prime is 35421200212397. The next prime is 35421200212457.

35421200212453 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 35421200212453 - 2³³ = 35412610277861 is a prime.

It is a super-4 number, since 4×35421200212453⁴ (a number of 55 digits) contains 4444 as substring. Note that it is a super-d number also for d = 3, 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (35421200212457) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1610054555101 + ... + 1610054555122.

It is an arithmetic number, because the mean of its divisors is an integer number (9660327330672).

Almost surely, 2^{35421200212453} is an apocalyptic number.

It is an amenable number.

35421200212453 is a deficient number, since it is larger than the sum of its proper divisors (3220109110235).

35421200212453 is a wasteful number, since it uses less digits than its factorization.

35421200212453 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3220109110234.

The product of its (nonzero) digits is 57600, while the sum is 34.

It can be divided in two parts, 35421200 and 212453, that added together give a palindrome (35633653).

The spelling of 35421200212453 in words is "thirty-five trillion, four hundred twenty-one billion, two hundred million, two hundred twelve thousand, four hundred fifty-three".