Base | Representation |
---|---|
bin | 100000111111010001… |
… | …010011110011100111 |
3 | 10101102120022110100012 |
4 | 200333101103303213 |
5 | 1040020314144201 |
6 | 24134452040435 |
7 | 2362525401614 |
oct | 407721236347 |
9 | 111376273305 |
10 | 35421240551 |
11 | 14027404324 |
12 | 6a4660311b |
13 | 3456591248 |
14 | 1a0043d50b |
15 | dc4a3c5bb |
hex | 83f453ce7 |
35421240551 has 4 divisors (see below), whose sum is σ = 36961294512. Its totient is φ = 33881186592.
The previous prime is 35421240527. The next prime is 35421240557. The reversal of 35421240551 is 15504212453.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 35421240551 - 218 = 35420978407 is a prime.
It is a super-3 number, since 3×354212405513 (a number of 33 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (35421240557) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 770026946 + ... + 770026991.
It is an arithmetic number, because the mean of its divisors is an integer number (9240323628).
Almost surely, 235421240551 is an apocalyptic number.
35421240551 is a deficient number, since it is larger than the sum of its proper divisors (1540053961).
35421240551 is a wasteful number, since it uses less digits than its factorization.
35421240551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1540053960.
The product of its (nonzero) digits is 24000, while the sum is 32.
The spelling of 35421240551 in words is "thirty-five billion, four hundred twenty-one million, two hundred forty thousand, five hundred fifty-one".
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