Base | Representation |
---|---|
bin | 110011100011000111110… |
… | …011111101110011110111 |
3 | 110112122120022121110220212 |
4 | 303203013303331303313 |
5 | 431014321231343112 |
6 | 11311205240220035 |
7 | 513634051402463 |
oct | 63430763756367 |
9 | 13478508543825 |
10 | 3542405340407 |
11 | 114636451204a |
12 | 49266046a61b |
13 | 1c908016887b |
14 | c364bd374a3 |
15 | 6222d0dc522 |
hex | 338c7cfdcf7 |
3542405340407 has 2 divisors, whose sum is σ = 3542405340408. Its totient is φ = 3542405340406.
The previous prime is 3542405340389. The next prime is 3542405340491. The reversal of 3542405340407 is 7040435042453.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3542405340407 - 230 = 3541331598583 is a prime.
It is a super-3 number, since 3×35424053404073 (a number of 39 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3542405330407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1771202670203 + 1771202670204.
It is an arithmetic number, because the mean of its divisors is an integer number (1771202670204).
Almost surely, 23542405340407 is an apocalyptic number.
3542405340407 is a deficient number, since it is larger than the sum of its proper divisors (1).
3542405340407 is an equidigital number, since it uses as much as digits as its factorization.
3542405340407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 806400, while the sum is 41.
The spelling of 3542405340407 in words is "three trillion, five hundred forty-two billion, four hundred five million, three hundred forty thousand, four hundred seven".
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