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354245003522741 is a prime number
BaseRepresentation
bin101000010001011110001011…
…1100110010011001010110101
31201110021111021101011001210002
41100202330113212103022311
5332412422231400211431
63253225524043241045
7134421233264621102
oct12042742746231265
91643244241131702
10354245003522741
11a296750a382081
123389307ab19185
13122882117b8086
14636979a369aa9
152ae4ad37d53cb
hex1422f179932b5

354245003522741 has 2 divisors, whose sum is σ = 354245003522742. Its totient is φ = 354245003522740.

The previous prime is 354245003522719. The next prime is 354245003522749. The reversal of 354245003522741 is 147225300542453.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 324283381936900 + 29961621585841 = 18007870^2 + 5473721^2 .

It is a cyclic number.

It is not a de Polignac number, because 354245003522741 - 238 = 353970125615797 is a prime.

It is a super-3 number, since 3×3542450035227413 (a number of 45 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (354245003522749) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 177122501761370 + 177122501761371.

It is an arithmetic number, because the mean of its divisors is an integer number (177122501761371).

Almost surely, 2354245003522741 is an apocalyptic number.

It is an amenable number.

354245003522741 is a deficient number, since it is larger than the sum of its proper divisors (1).

354245003522741 is an equidigital number, since it uses as much as digits as its factorization.

354245003522741 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4032000, while the sum is 47.

The spelling of 354245003522741 in words is "three hundred fifty-four trillion, two hundred forty-five billion, three million, five hundred twenty-two thousand, seven hundred forty-one".