3545012503 has 2 divisors, whose sum is σ = 3545012504. Its totient is φ = 3545012502.

The previous prime is 3545012501. The next prime is 3545012507. The reversal of 3545012503 is 3052105453.

3545012503 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (3052105453) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3545012503 - 2¹ = 3545012501 is a prime.

It is a super-2 number, since 2×3545012503² = 25134227292852650018, which contains 22 as substring.

Together with 3545012501, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3545012501) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1772506251 + 1772506252.

It is an arithmetic number, because the mean of its divisors is an integer number (1772506252).

Almost surely, 2^3545012503 is an apocalyptic number.

3545012503 is a deficient number, since it is larger than the sum of its proper divisors (1).

3545012503 is an equidigital number, since it uses as much as digits as its factorization.

3545012503 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9000, while the sum is 28.

The square root of 3545012503 is about 59540.0075831369. The cubic root of 3545012503 is about 1524.7755653590.

Adding to 3545012503 its reverse (3052105453), we get a palindrome (6597117956).

The spelling of 3545012503 in words is "three billion, five hundred forty-five million, twelve thousand, five hundred three".