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355153411139 is a prime number
BaseRepresentation
bin1010010101100001100…
…10101111110001000011
31020221201020210121110012
411022300302233301003
521304323233124024
6431053310055135
734442014120352
oct5126062576103
91227636717405
10355153411139
1112768a92941a
12589b81aa4ab
132764c451927
1413292069999
1593896b050e
hex52b0cafc43

355153411139 has 2 divisors, whose sum is σ = 355153411140. Its totient is φ = 355153411138.

The previous prime is 355153411103. The next prime is 355153411141. The reversal of 355153411139 is 931114351553.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (931114351553) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 355153411139 - 224 = 355136633923 is a prime.

It is a super-2 number, since 2×3551534111392 (a number of 24 digits) contains 22 as substring.

Together with 355153411141, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 355153411096 and 355153411105.

It is not a weakly prime, because it can be changed into another prime (355150411139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 177576705569 + 177576705570.

It is an arithmetic number, because the mean of its divisors is an integer number (177576705570).

Almost surely, 2355153411139 is an apocalyptic number.

355153411139 is a deficient number, since it is larger than the sum of its proper divisors (1).

355153411139 is an equidigital number, since it uses as much as digits as its factorization.

355153411139 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 121500, while the sum is 41.

The spelling of 355153411139 in words is "three hundred fifty-five billion, one hundred fifty-three million, four hundred eleven thousand, one hundred thirty-nine".