Search a number
-
+
355962113231213 is a prime number
BaseRepresentation
bin101000011101111101110001…
…1010100000000100101101101
31201200100122102201000010122102
41100323323203110000211231
5333124040401441344323
63301022423131424445
7134656262000413466
oct12073734324004555
91650318381003572
10355962113231213
11a34697590078a5
1233b0ba135b5125
1312381110b766a8
1463c8930193d6d
152b245d124c328
hex143bee350096d

355962113231213 has 2 divisors, whose sum is σ = 355962113231214. Its totient is φ = 355962113231212.

The previous prime is 355962113231191. The next prime is 355962113231269. The reversal of 355962113231213 is 312132311269553.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 351685398238729 + 4276714992484 = 18753277^2 + 2068022^2 .

It is an emirp because it is prime and its reverse (312132311269553) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 355962113231213 - 210 = 355962113230189 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (355962113231293) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 177981056615606 + 177981056615607.

It is an arithmetic number, because the mean of its divisors is an integer number (177981056615607).

Almost surely, 2355962113231213 is an apocalyptic number.

It is an amenable number.

355962113231213 is a deficient number, since it is larger than the sum of its proper divisors (1).

355962113231213 is an equidigital number, since it uses as much as digits as its factorization.

355962113231213 is an evil number, because the sum of its binary digits is even.

The product of its digits is 874800, while the sum is 47.

The spelling of 355962113231213 in words is "three hundred fifty-five trillion, nine hundred sixty-two billion, one hundred thirteen million, two hundred thirty-one thousand, two hundred thirteen".